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--- classes:2009:fall:phys4101.001:lec_notes_0925 [2009/09/28 23:53] – x500_moore616
+++ classes:2009:fall:phys4101.001:lec_notes_0925 [2009/09/28 23:56] (current) – x500_moore616
@@ Line 43: / Line 43: @@
 Differentiate and then Schrodinger's equation becomes
-<math> \frac{\partial^2h(\xi)}{\partial \xi^2}=-2h\xi(\xi)+(K-1)(h(\xi)=0 </math> (A)
+<math> \frac{\partial^2h(\xi)}{\partial \xi^2}=-2h\xi(\xi)+(K-1)(h(\xi)=0 \ \ \ \ \ \ \ \ (A) </math>